Question

In the compound $\begin{array}{ccc}& C{H}_3& \\ & |& \\ HC\equiv C& -C=& C{H}_2\end{array}$ the hybridisation of $C-2$ and $C-3$ carbons are respectively:

• A. ${sp}^3$ and ${sp}^3$
• B. ${sp}^2$ and ${sp}^3$
• C. ${sp}^2$ and $sp$
• D. ${sp}^3$ and $sp$

Answer 1

The correct option is C ${sp}^2$ and $sp$

$C_2=3\sigma$ bonds $\Rightarrow {sp}^2$ hybridisation

$C_3=2\sigma$ bonds $\Rightarrow sp$ hybridisation