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Electronegativity

In the compou...

Question

In the compound $M - O - H$ , in $a q .$ medium the $M - O$ bond will be broken if:

Δ

(E . N .)

M

and

O

< Δ

(E . N .)

O

and

H

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Δ

(E . N .)

M

and

O

= Δ

(E . N .)

O

and

H

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Δ

(E . N .)

M

and

O

> Δ

(E . N .)

O

and

H

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cannot be predicated according

Δ

(E . N .)

data

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Solution

The correct option is C $Δ$ $(E . N .)$ of $M$ and $O$ $> Δ$ $(E . N .)$ of $O$ and $H$
If electronegativity difference of $M - O$ is greater than $O - H$ , then $M - O$ bond will be broken and $M^{+}$ and $O H^{-}$ ions will form.

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Similar questions

Calculate the heat of combustion (in KJ) of

methane from the following data

i) C (graphite) + 2H $_{2}$ (g) $\to$ CH $_{4}$ (g), $Δ$ H = -74.8 kJ

ii) C (graphite) + O $_{2}$ (g) $\to$ CO $_{2}$ (g), $Δ$ H = -393.5 kJ

iii) H $_{2}$ (g) +1/2O $_{2}$ (g) $\to$ H $_{2}$ O $(l)$ , $Δ$ H = -286.2 KJ.

S b F_{3}

S b F_{5}

M - O - H,

M - O

^{o}

^{o}

Δ

Δ

(G i v e n C_{v} = \frac{3}{2} R)

Δ

Δ

Δ

Δ

Δ

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