In the compound-6CH2 - 5CH - 4CH2 - 3CH2 -2C-1CH- C2-C3 bond is of -

The chain is 6CH_2 = nbsp;5CH nbsp;4CH_2 nbsp;3CH_2 2C≡ nbsp;1CH nbsp; Hence, C_2 C_3 are sp sp^3 hybridised. nbsp; ...

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Organic Compounds

In the compou...

Question

In the compound, $6 C H_{2} = 5 C H - 4 C H_{2} - 3 C H_{2} - 2 C \equiv 1 C H$ , $C_{2} - C_{3}$ bond is of :

s p - s p^{2}

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s p - s p^{3}

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s p^{2} - s p^{3}

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s p^{3} - s p^{3}

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6 C H_{2} = 5 C H - 4 C H_{2} - 3 C H_{2} - 2 C H \equiv 1 C H_{2}

C_{2} - C_{3}

C H_{2} = C H - C H_{2} - C H_{2} - C \equiv C H

C_{2} - C_{3}

C H_{2} = C H - C H_{2} - C H_{2} - C \equiv C H

C_{2} - C_{3}

C H_{2} = C H - C H_{2} - C H_{2} - C \equiv C H

C_{2} - C_{3}

In the organic compound CH₂=CH–CH₂–CH₂–C≡CH, the pair of hydridised orbitals involved in the formation of: C₂ – C₃ bond is:

(a) sp – sp²(b) sp – sp³(c) sp² – sp³ (d) sp³– sp³

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