In the compound- CH 2- CH - CH 2- CH 2- CH - CH 2- C 2- C 3 bond is of -A- sp - sp 2B- sp - sp 3C- sp 3- sp 3D- sp 2- sp 3

The chain is 6CH_2 = nbsp;5CH nbsp;4CH_2 nbsp;3CH_2 2C≡ nbsp;1CH nbsp; Hence, C_2 C_3 are sp sp^3 hybridised. nbsp; ...

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Standard XII

Chemistry

Organic Compounds

In the compou...

Question

In the compound, $6 C H_{2} = 5 C H - 4 C H_{2} - 3 C H_{2} - 2 C H \equiv 1 C H_{2}$ , $C_{2} - C_{3}$ bond is of :

s p - s p^{2}

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s p - s p^{3}

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s p^{2} - s p^{3}

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s p^{3} - s p^{3}

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Solution

The correct option is B $s p - s p^{3}$
The chain is
$6 C H_{2} = 5 C H - 4 C H_{2} - 3 C H_{2} - 2 C H \equiv 1 C H_{2}$

Hence, $C_{2} - C_{3}$ are $s p - s p^{3}$ hybridised.

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Similar questions

In the organic compound $C H_{2} = C H - C H_{2} - C H_{2} - C \equiv C H$ , the pair of hydridised orbitals involved in the formation of: $C_{2} - C_{3}$ bond is:
(a) $s p - s p^{2}$ (b) $s p - s p^{3}$ (c) $s p^{2} - s p^{3}$ (d) $s p^{3} - s p^{3}$