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Organic Compounds

In the compou...

Question

In the compound, $6 C H_{2} = 5 C H - 4 C H_{2} - 3 C H_{2} - 2 C \equiv 1 C H$ , $C_{2} - C_{3}$ bond is of :

A

s p - s p^{2}

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B

s p - s p^{3}

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C

s p^{2} - s p^{3}

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D

s p^{3} - s p^{3}

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Solution

The correct option is B $s p - s p^{3}$
The chain is
$6 C H_{2} = 5 C H - 4 C H_{2} - 3 C H_{2} - 2 C \equiv 1 C H$

Hence, $C_{2} - C_{3}$ are $s p - s p^{3}$ hybridised.

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Organic Compounds

Standard XII Chemistry

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