Question

In the compound, what is the hybridisation of the $C_4$ and $C_5$ carbon atoms?

• A. $sp-s{p}^2$
• B. $s{p}^3-sp$
• C. $sp-s{p}^3$
• D. $s{p}^2-s{p}^2$

Answer 1

The correct option is D $s{p}^2-s{p}^2$

In the compound the $C_4$ and $C_5$ is the type of $s{p}^2-s{p}^2$. The numbering is done in such a way that C atoms attached to double bonds, get the lowest locants. Thus, second and third C atoms are attached by a double bond and have $s{p}^2$ hybridization.