In the compounds shown above, the correct order of acidity is :

I > IV > III > II

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II > IV > I > II

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II > I > III > IV

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IV > III > I > II

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Solution

The correct option is A IV > III > I > II
$C H_{3}$ is an activating group and hence decreases acidity of phenol.

$N O_{2}$ is a deactivating group and hence increases acidity of phenol.

Para positions are more effective than meta positions.

Hence, reactivity is $I V > I I I > I > I I$ .

Option D is correct.

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Similar questions

Q. Identify the rate of reaction of given compounds in

E_{2}

reactions

Q. Make the correct match
A

V
I

V
V

Mark the correct order of decreasing acid strength of the following compounds.

(a) V > IV > II > I > III
(b) II > IV > I > III > V
(c) IV > V > III > II > I
(d) V > IV > III > II > I

Order of decreasing acidity of

$(i) H C O O H (i i) C H_{3} C O O H (i i i) C l_{2} C H C O O H (i v) C F_{3} C O O H i s$

Q. Consider the following phenols

The decreasing order of acidic nature of the above phenols is :

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In the compounds shown above, the correct order of acidity is :

The correct option is A IV > III > I > IICH3 is an activating group and hence decreases acidity of phenol.NO2 is a deactivating group and hence increases acidity of phenol.Para positions are more effective than meta positions.Hence, reactivity is IV>III>I>II.Option D is correct.