In the concentration cell PtH2HA 0-1 M NaA 1MHA1 M NaA1MH2Pt pKa of HA - 4Cell potential will be-

The correct option is A 0.06 V E_cell = 0.05911log_10[H^+]Cathode[H^+]Anode E_cell = 0.06 [pH Anode pH Cathode] .... (1) pH Anode = pK_a ...

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In the concen...

Question

In the concentration cell
$P t (H_{2}) ∣ ∣ ∣ \begin{matrix} H A (0.1 M) N a A (1 M) \end{matrix} ∣ ∣ ∣ ∣ ∣ ∣ \begin{matrix} H A (1 M) N a A (1 M) \end{matrix} ∣ ∣ ∣ (H_{2}) P t$
$(p K_{a}$ of $H A = 4$ )
Cell potential will be:

0.03 V

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0.06 V

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- 0.06 V

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- 0.03 V

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