In the conplex reactions is the molecularity and order same of the slowest step?

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Solution

Not Always

Order of complex reaction equal to molecularity of its slowest step when slowest step reactants does not involves any intermediate of the reaction.

If intermediate is involved then we have to eliminate it using equilibrium step

Note:Molecularity and order of reaction are same only for single step elementary reaction

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Similar questions

For a complex reaction ......... .

(a) order of overall reaction is same as molecularity of the slowest step
(b) order of overall reaction is less than the molecularity of the slowest step
(c) order of overall reaction is greater than molecularity of the slowest step
(d) molecularity of the slowest step is never zero or non-integer

X s t e p I - -- \to Y s t e p I I - --- \to Z

is a complex reaction. Total order of reaction is 2 and step II is the slowest step. What is molecularity of step II?

Q. Assertion :Complex reaction takes place in different steps and the slowest step determines the rate of reaction. Reason: Order and molecularity of a reaction are always equal.

Q. Which of the following statements are correct?

(i) Law of mass action and rate law expressions are same for single step reaction.
(ii) Order of the slowest elementary reaction of a complex reaction gives the order of the complex reaction.
(iii) Both order and molecularity have normally a maximum value of 3.
(iv) Molecularity of a complex reaction

A + 2 B \to C

is 3.

In any unimolecular reaction ......... .
(a) only one reacting species is involved in the rate determining step
(b) the order and the molecularity of slowest step are equalto one
(c) the molecularity of the reaction is one and order is zero
(d) both molecularity and order of the reaction are one

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