Question

In the context of carbon, which of the following is arranged in the correct order of electronegativity.

• A. $sp>s{p}^2>s{p}^3$
• B. $s{p}^3>s{p}^2>sp$
• C. $s{p}^2>sp>s{p}^3$
• D. $s{p}^3>sp>s{p}^2$

Answer 1

The correct option is A $sp>s{p}^2>s{p}^3$

The correct order regarding electronegativity of hybrid orbitals of carbon is $sp>s{p}^2>s{p}^3$ because in $sp>s{p}^2>s{p}^3$ hybrid orbitals $s-$ orbital character is $50\%,33.3\%$ and $25\%$ respectively and due to higher $s-$ orbital character electron attraction tendency therefore electronegativity increases.