Question

In the conversion $B{r}_2\to Br{O}_3^{-}$, the oxidation state of Bromine changes from :

• A. $-5$ to $0$
• B. $-5$ to $+5$
• C. $0$ to $+5$
• D. $-1$ to $+1$

Answer 1

The correct option is C $0$ to $+5$

Since $B{r}_2$ molecule is in its natural state and is a neutral molecule. So it has a $0$ charge
In case of $Br{O}_3^{-}$, let the charge on Bromine be $x$
Charge on oxygen $=-2$
Overall charge $=-1$
$x+(3\times -2)=-1x=+5$
$\therefore$ oxidation state of Bromine changes from $0$ to $+5$