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Valency and Oxidation State

In the conver...

Question

In the conversion

$N H_{2} O H ⟶ N_{2} O$

the equivalent weight of $N H_{2} O H$ will be

$\frac{M}{4}$

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$\frac{M}{2}$

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$\frac{M}{5}$

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$\frac{M}{4}$

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Solution

The correct option is B
$\frac{M}{2}$

$N H_{2} O H ⟶ N_{2} O$

n- factor =2

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