In the conversion of $B r_{2} \to B r O_{3}^{-},$ the oxidation state of bromine changes from

–1 to –1

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0 to –1

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0 to +5

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0 to –5

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Solution

The correct option is C 0 to +5
${0 B r}_{2} \to + 5 B r O_{3}^{-}$

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Similar questions

In the conservation $B r_{2} ⟶ B R O_{3}^{-}$ , the oxidation state of bromine changes from

B r_{2} \to B r O_{3}^{-}

B r_{2}

B r O_{3}^{-}

C l_{2} + H_{2} S ⟶ 2 H C l + S

B r_{2} \to B r O_{3}^{-}

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