Question

In the conversion of $C_2{H}_4$ to $C_2{H}_6$ breakage of one $\pi$ bond accounts for formation of _____ $\sigma$ bond.

• A. $1$
• B. $2$
• C. $3$
• D. $0$

Answer 1

The correct option is B $2$

In the conversion of $C_2{H}_4$ to $C_2{H}_6$ breakage of one $\pi$ bond accounts for formation of two new $\sigma$ bonds.

$C{H}_2=C{H}_2$ + $H_2/Pt\to C{H}_3-C{H}_3$.