Question

In the coordination compound, $K_4\left[Ni\right(CN{)}_4]$, the oxidation state of nickel is

• A. $+2$
• B. $+1$
• C. $0$
• D. $+4$

Answer 1

The correct option is C $0$

Let the oxidation state of $Ni$ is $x$.
So, in the compound $K_4\left[Ni\right(CN{)}_4]$
$4\times (+1)+x+4\times (-1)=0\Rightarrow x=0$
$\therefore$ The oxidation state of $Ni$ is $0$.