In the cubic close packing, this unit cell has:

4 tetrahedral voids each of which is shared by four adjacent unit cells.

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4 tetrahedral voids within the unit cell.

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8 tetrahedral voids each of which is shared by four adjacent unit cell.

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8 tetrahedral voids within the unit cells.

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Solution

The correct option is D 8 tetrahedral voids within the unit cells.
Since, cube close packing is analogous to face-centered cubic (fcc) structure and number of atoms in a fcc crystal is $4 p e r u n i t c e l l$

So, number of tetrahedral voids $= 2 \times N u m b e r o f a t o m s i n u n i t c e l l$

$= 2 \times 4 = 8$
Hence, Option "D" is the correct answer.

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Similar questions

In the cubic close packing, the unit cell has

(a) 4 tetrahedral voids each of which is shared by four adjacent unit cell

(b) 4 tetrahedral voids within the unit cell

(d) 8 tetrahedral voids within the unit cells

Show that in a cubic packed structure, eight tetrahedral voids are present per unit cell.

What is the number of tetrahedral voids in FCC Unit cell?

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