In the current circuit diagram when the current reaches steady state in the circuit, the charge on the capacitor of capacitance C will be

C E \frac{r_{2}}{(r + r_{2})}

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C E \frac{r_{1}}{(r_{1} + r)}

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C E

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C E \frac{r_{1}}{(r_{2} + r)}

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Solution

The correct option is A $C E \frac{r_{2}}{(r + r_{2})}$
$I = \frac{E}{r + r_{2}}$
$V = I r_{2}$
$Q = C V$
$Q = C E \frac{r_{2}}{(r + r_{2})}$

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