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Question

In the decay process:
A−α−−−−−→B−β−−−−−→C−β−−−−−→D

A
A and B are isodiapheres
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B
A and D are isotopes
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C
B, C and D are isobars
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D
A and C are isotones
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Solution

The correct options are
A A and B are isodiapheres
B A and D are isotopes
C B, C and D are isobars
AZ[A]αA4Z2[B]βA4Z1CβA4ZD
A & D are isotopes.
B,C & D are isobars.
Isodiaphers have same value of n-p.
For A n-p = A-2Z
For B n-p = (A-4) -2(Z-2) = A-2Z
A & B are isodiaphers.

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