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Question

In the determination of P, an aqueous solution of NaH2PO4 is treated with a mixture of ammonium and magnesium ions to precipitate magnesium ammonium phosphate, Mg(NH4)PO4.6H2O. This was heated and yielded 3.33 g of Mg2P2O7. What weight of NaH2PO4 was present originally?

A
3.6 g
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B
3.9 g
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C
4.5 g
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D
4.8 g
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Solution

The correct option is A 3.6 g
Weight of P in 3.33 g of Mg2P2O7 =62×3.33222=0.93 g.
As this P is present in reactant, so mass of reactant =120×0.9331=3.6 g.

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