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B
0.65 V
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C
- 0.35 V
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D
- 0.65 V
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Solution
The correct option is A 0.325 V Given,Cu2++e−→Cu+;E01=0.15V ∴ΔG01=−1×0.15×F=−0.15F Again, Cu++e−→Cu;E02=−0.5V ∴ΔG02=−1×0.50×F=−0.5F Now, Cu+2+2e−→Cu;E03=?∴ΔG03=−2×E03×F=−2E03FAlso,ΔG03=ΔG01+ΔG02=−0.15F−0.5F⇒−2E03F=−0.65ForE03=0.652=0.325V