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Question


In the diagram, PQ is a tangent to the circle at P and QRS is a straight line. Then the value of x is:
95605.png

A
20o
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B
25o
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C
30o
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D
40o
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Solution

The correct option is B 25o
From the given figure,
TPS=PSQ+SQP ..... [exterior angle of a triangle is equal to interior opposite angle]
65=x+40x=25o

(Alternate Method)
m(P)=65o
m(SPQ)=18065=115o
Now in triangle SPQ,
Sum of all angles of SPQ will be equal to 180o
x+115o+40o=180o
x=25o
Hence, option B is correct.

85471_95605_ans_f6f338f1e0a44ee1a7c182e4f6e301ac.png

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