Question

# In the diagram shown , a light ray is incident on the lower medium boundary at an angle 45o with the normal

A
If μ2<2 then deviation suffered by the light ray is 90o
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B
If μ2>2 then total deviation suffered by the light ray is 45o
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C
If μ2>2 then total deviation suffered by light ray is 90o
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D
If μ2>2 then total deviation suffered by light ray is 45o
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Solution

## The correct option is B If μ2<√2 then deviation suffered by the light ray is 90oFor μ2⟩√2 (TIR will not take place) - (1)sin45sinγ=μ22⇒μ2=x√2√2sinγ⇒√2sinγ>√2 ( using-1) ⇒sinγ<1γ<90∘So, deviation is approx 45∘If μ2<√2, TIR will take, Then deviation must be 90∘ or more

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