In the diagram shown in figure- match the following- g -10 m - s 2a - text Acceeration of 2 kg block - p - t e x t 8 SI unit hlinec - ltext Normal reaction between 2 kg and 1 kg - r - text 2 SI unit hlined - 1 text Normal reaction between 3 kg and 2 kg - s - text45 N hline -text t - -endarray A- a - r - b - t - c - q - d - p B- a - r - b - t - c - t - d - q C- a - p- b - t- c - q- d - t

The correct option is D (a) – (r); (b) – (t); (c) – (q); (d) – (t)(a) a = 42N 6 × g × sin 30^∘/6 = 2ms^ 2 (b) F_net on 3kg = 3 × a = 6N (c) R_1 1 × g sin ...

You visited us 4 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Second Law of Motion

In the diagra...

Question

In the diagram shown in figure, match the following: $(g = 10 m / s^{2})$

$\begin{matrix} Column -I & Column-II (a) & Acceeration of 2 kg block & (p) & 8 SI unit (b) & Net force on 3 kg block & (q) & 25 SI unit (c) & Normal reaction between 2 kg and 1 kg & (r) & 2 SI unit (d) & Normal reaction between 3 kg and 2 kg & (s) & 45 N (t) & None \end{matrix}$

(a) – (r); (b) – (t); (c) – (q); (d) – (p)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a) – (r); (b) – (t); (c) – (t); (d) – (q)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a) – (p); (b) – (t); (c) – (q); (d) – (t)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a) – (r); (b) – (t); (c) – (q); (d) – (t)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D (a) – (r); (b) – (t); (c) – (q); (d) – (t)
$(a) a = \frac{42 N - 6 \times g \times s i n 30^{\circ}}{6} = 2 m s^{- 2}$

(b) $F_{n e t}$ on 3kg = $3 \times a = 6 N$

(c) $R_{1} - 1 \times g s i n 30^{\circ} - 18 = 1 \times a$

$R_{1} = 18 + 5 + 2 = 25 N$

(d) $60 N - R_{2} - 3 \times g s i n 30^{\circ} = 3 \times 2$

$R_{2} = 60 - 15 - 6 = 39 N$

Suggest Corrections

173

Similar questions

Q. In the figure, all pulleys are massless and strings are light. Take

g = 10 m s^{- 2}

\begin{matrix} Column-I & Column-II (a) 1 kg block & (p) will remain stationary (b) 2 kg block & (q) will move down (c) 3 kg block & (r) will move up (d) 4 kg block & (s) 5 m / s^{2} (t) 10 m / s^{2} \end{matrix}

Q. Match each of the reactions given in

C o l u m n I

with the corresponding product(s) given in

C o l u m n I I

\begin{matrix} C o l u m n I & C o l u m n I I A . & C u + d i l . H N O_{3} & p . & N O B . & C u + c o n c . H N O_{3} & q . & N O_{2} C . & Z n + d i l . H N O_{3} & r . & N_{2} O D . & Z n + c o n c . H N O_{3} & s . & C u (N O_{3})_{2} t . & Z n (N O_{3})_{2} \end{matrix}

Q. In the diagram shown in figure, match the following:

(g = 10 m / s^{2})

\begin{matrix} Column -I & Column-II (a) & Ultraviolet light & (p) & n = 6 \to n = 3 (b) & Visible light & (q) & n = 3 \to n = 1 (c) & Infrared radiation & (r) & n = 4 \to n = 2 (d) & Micro wave & (s) & n = 7 \to n = 6 \end{matrix}

Match the following:

$\begin{matrix} a) Lyman (r, t) & p) visible b) Balmer (p) & q) Infrared c) Paschen (q, s) & r) Ultraviolet d) Brackett (q) & s) n_{2} = 4, n_{1} = 3 t) n_{2} = 5, n_{1} = 1 \end{matrix}$

Match the column:
$\begin{matrix} Column-I & Column-II (a) & Anglesite & (p) & Sulphate ore (b) & Galena & (q) & Sulphide ore (c) & Cerussite & (r) & Ore of Pb (d) & Cinnabar & (s) & Carbonate ore (t) & Ore of Hg \end{matrix}$

Join BYJU'S Learning Program

In the diagram shown in figure, match the following: (g=10m/s2) Column -IColumn-II(a)Acceeration of 2 kg block(p)8 SI unit(b)Net force on 3 kg block(q)25 SI unit(c)Normal reaction between 2 kg and 1 kg(r)2 SI unit(d)Normal reaction between 3 kg and 2 kg(s)45 N (t)None

The correct option is D (a) – (r); (b) – (t); (c) – (q); (d) – (t)(a) a=42N−6×g×sin30∘6=2ms−2 (b) Fnet on 3kg = 3×a=6N (c) R1−1× g sin 30∘−18=1×a R1=18+5+2=25N (d) 60N−R2−3×gsin30∘=3×2 R2=60−15−6=39N