In the diagram shown in figure- match the following- g -10 m - s 2 beginarray -c-c- hlinea - -text Ultraviolet light -p - n-6 trightarrow n-3 l l hlineb - text Visible light -q - n-3 rightarrow n-1 hlined - -text Micro wave - s - n -7 rightarrow n -6 ll hline endarray A- a - p- b - q- c - r - d - s B- a- q- b - p- c - r- d - sC- a - q- b - r- c - p- d - sD- a - s- b - r- c - q- d - p

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Byju's Answer

Standard XII

Physics

Expression for Standing Waves

In the diagra...

Question

In the diagram shown in figure, match the following: $(g = 10 m / s^{2})$
$\begin{matrix} Column -I & Column-II (a) & Ultraviolet light & (p) & n = 6 \to n = 3 (b) & Visible light & (q) & n = 3 \to n = 1 (c) & Infrared radiation & (r) & n = 4 \to n = 2 (d) & Micro wave & (s) & n = 7 \to n = 6 \end{matrix}$

(a) – (p); (b) – (q); (c) – (r); (d) – (s)

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(a) – (q); (b) – (r); (c) – (p); (d) – (s)

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(a) – (q); (b) – (p); (c) – (r); (d) – (s)

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(a) – (s); (b) – (r); (c) – (q); (d) – (p)

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Solution

The correct option is B (a) – (q); (b) – (r); (c) – (p); (d) – (s)
When electron jumps from one energy level to another, it eithers absorbs or releases energy. As a result of this transitions, electromagnetic waves are produced. We get different waves for different transitions.

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\begin{matrix} C o l u m n - I & C o l u m n - I I (a) & Kinetic energy & (p) & - \frac{G M m}{2 r} (b) & Potential energy & (q) & \sqrt{\frac{G M}{r}} (c) & Total energy & (r) & - \frac{G M m}{r} (d) & Orbital velocity & (s) & \frac{G M m}{2 r} \end{matrix}

\begin{matrix} Column I & Column II a. The sides of a triangle vary slightly in such a way that its circum-radius & p. 1 remains constant. If \frac{d a}{cos A} + \frac{d b}{cos B} + \frac{d c}{cos C} + 1 = | m |, then the value of m is b. The length of sub-tangent to the curve x^{2} y^{2} = 16 at the point (-2, 2) is |k|. & q. - 1 Then the value of k is c. The curve y = 2 e^{2 x} intersects the y-axis at an angle {cot}^{- 1} ∣ ∣ ∣ \frac{8 n - 4}{3} ∣ ∣ ∣ . & r. 2 Then the value of n is d. The area of a triangle formed by normal at the point (1, 0) on the curve & s. - 2 x = e^{sin y} with axes is \frac{| 2 t + 1 |}{6} sq. units. Then the value of t is \end{matrix}

Which of the following is correct ?

Q. Match the following:

A particle suspended from a string of length is given a horizo ntal speed

u = 3 \sqrt{g l}

at the bottom. Then for the particle match the following column

\begin{matrix} Column -I & Column-II (a) & Speed at B & (p) & 7 mg (b) & Speed at C & (q) & \sqrt{5 g l} (c) & Tension in string at B & (r) & \sqrt{7 g l} (d) & Tension in string at C & (s) & 4 mg \end{matrix}

Match the two columns.
$\begin{matrix} C o l u m n - I & C o l u m n - I I (A) A b s c i s s a & (p) x (B) O r d i n a t e & (q) y (C) C o - o r d i n a t e & (r) x, y (D) O r i g i n & (s) 0 \end{matrix}$
Choose the correct option:

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In the diagram shown in figure, match the following: (g=10m/s2) Column -IColumn-II(a)Ultraviolet light(p)n=6→n=3(b)Visible light(q)n=3→n=1(c)Infrared radiation(r)n=4→n=2(d)Micro wave(s)n=7→n=6

The correct option is B (a) – (q); (b) – (r); (c) – (p); (d) – (s)When electron jumps from one energy level to another, it eithers absorbs or releases energy. As a result of this transitions, electromagnetic waves are produced. We get different waves for different transitions.

The correct option is B (a) – (q); (b) – (r); (c) – (p); (d) – (s)
When electron jumps from one energy level to another, it eithers absorbs or releases energy. As a result of this transitions, electromagnetic waves are produced. We get different waves for different transitions.