In the dissociation of $2 H I ⇌ H_{2} + I_{2}$ , the degree of dissociation will be affected by the :

addition of inert gas

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addition of

H_{2}

I_{2}

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increase of temperature

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increase of pressure

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Solution

The correct options are
B addition of $H_{2}$ or $I_{2}$
C increase of temperature
In the dissociation of $2 H I ⇌ H_{2} + I_{2}$ , the degree of dissociation will be affected by the addition of $H_{2}$ or $I_{2}$ and increase of temperature.
By the addition of $H_{2}$ or $I_{2}$ , the reaction will moves towards backward direction and it will supresses the dissociation of $H I$ .
Increase of temperature, moves the reactions towards forward direction and it will promotes the dissociation of $H I$ .

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Similar questions

2 H I

⇌

H_{2} + I_{2}

α

Total number of moles for the reaction $2 H I ⇋ H_{2} + I_{2}$ if $α$ is degree of

dissociation is

K_{c}

H I

H_{2} (g)

I_{2} (g)

H I

H_{2} + I_{2} ⇌ 2 H I

2 H I (g) ⇌ H_{2} (g) + I_{2} (g)

H I

2 H I ⇌ H_{2} + I_{2}

450^{o} C

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