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Question

In the dissociation of PCl5 as:
PCl5(g)PCl3(g)+Cl2(g) if the degree of dissociation is α at equilibrium pressure P, then the the equilibrium constant for the reaction is:

A
Kp=α21+α2P
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B
Kp=α2P21α2P
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C
Kp=αP21α2
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D
Kp=α2P1+α2
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Solution

The correct option is C Kp=αP21α2
PCl5 (g) PCl3 (g) +Cl2 (g)
Initial t=01 0 0
At equilibrium 1α α α
Total number of molus =1α+α+α
=1+α

KP will known that partial pressure is the product of mole fraction and the total pressure role fraction is the number of moles of that component divided by the number of mole in mixture

PPCl5=(1α)p1+α,PPCl3=αP1+α , PPCl2=αP1+α
Kp=PPCl3.PCl2PPCl5
Put all these value:

kp=αP1+α.αP1+α(1α)P(1+α)α2p(1+α)2(1α)(1+α)=α2P1α2

kp=α2P1α2

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