In the double-slit experiment, the distance of the second dark fringe from the central line is 3mm. The distance of the fourth bright fringe from the central line is:
A
6mm
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B
8mm
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C
12mm
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D
16mm
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Solution
The correct option is B8mm Answer is B. The distance of 2nd dark fringe is given as =(1+12)β=3mm⇒β=2mm Therefore, distance of 4th bright fringe = 4β= 8 mm. Hence, the distance of the fourth bright fringe from the central line is 8 mm.