In the electric network shown, when no current flows through the 4Ω resistor in the arm EB, the potential difference between the points A and D will be:
A
3 V
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B
4 V
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C
5 V
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D
6 V
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Solution
The correct option is C 5 V
Applying kvl along ABED of i1=0 VA−9+4=VD⇒VA−VD=5V