In the electric network shown, when no current flows through the 4Ω resistor in the arm EB the potential difference between the points A and D will be
A
5V
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B
3V
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C
4V
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D
6V
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Solution
The correct option is A5V Let the potential of point B=0 ∴ Potential of point A and C will be 9V and 3V respectively. By applying KCL at E I1+I3=I2 as I3=0∴I1=I2 Also as I3=0 VE=VB+4=4volts VE=VD=4volts ∴ Potential difference between point A and D will be =VA−VD =(9−4)volts =5volts=5V (Thus option A)