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Question

In the electrochemical cell:
Zn|ZnSO4 (0.01M)|| CuSO4(1.0M)Cu, the emf of this Daniell cell is E1. When the concentration of ZnSO4 is changed to 1.0 M and that of CuSO4 changed to 0.01 M, the emf changes to E2. From the followings, which one is the relationship between E1 and E2? (Given, RT/F = 0.059)

A
E1<E2
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B
E1>E2
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C
E2=E1
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D
E1=E2
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Solution

The correct option is B E1>E2
Ecell=E0cell0.059n log[Zn2+][Cu2+]
E1=E00.0592 log0.010
E1=E0.0592 (2)=E+0.059
E2=E0.0592 log10.01=E0.059
Hence, E1>E2

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