In the electrochemical reaction- 2Fe3- - Zn - Zn2- - 2Fe2-increasing the concentration of Fe2-

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Electrolysis and Electrolytes

In the electr...

Question

In the electrochemical reaction,
$2 F e^{3 +} + Z n \to Z n^{2 +} + 2 F e^{2 +}$ ,
increasing the concentration of $F e^{2 +}$ :

increases the cell emf.

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increases the current flow.

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decreases the cell emf.

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alters the

p H

of the solution.

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Solution

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Similar questions

N i (s) + 2 F e^{3 +} \to N i^{2 +} + 2 F e^{2 +} i s N i (s) | N i^{2 +} (a q) | | F e^{3 +} (a q), F e^{2 +} (a q)

2 F e_{(a q)}^{+ 3} + Z n_{(s)} \to Z n_{(a q)}^{+ 2} + 2 F e_{(a q)}^{+ 2}

F e^{+ 2}

Z n \to Z n^{2 +} + 2 e^{-} (E_{(Z n^{2 +} / Z n)}^{0} = - 0.76 V)

F e \to F e^{2 +} + 2 e^{-} E^{0} = 0.41 V

F e^{2 +} + Z n \to Z n^{2 +} + F e

P t | H_{2} (x a t m) | H^{\oplus} (p H = y) | | Z n^{2 +} (z M) | Z n

E_{c e l l}^{⊖} = E_{c e l l}

2 {F e}_{(a q)}^{+ 3} + {Z n}_{(s)} \to {Z n}_{(a q)}^{+ 2} + 2 {F e}_{(a q)}^{+ 2}

{F e}^{+ 2}

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