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Question

# In the electrolysis of acidulated H2O, 11.2 litres of H2 gas is liberated at the cathode. The volume of O2 gas liberated at the anode is:

A
11.2 litres
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B
5.6 litres
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C
2.8 litres
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D
22.4 litres
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Solution

## The correct option is B 5.6 litres11.2 litre H2=0.5 moles of H2 at NTP2H++2e−→H21 mole of H2 requires 2 moles electrons.∴ The number of electrons required =0.5×2=1electronO2−→O2+2e−1 mole of O2 liberates 4 electrons.∴ Moles of O2 for 1 mole e−=1414mole at NTP=14×22.4=5.6 litres.

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