In the electrolysis of aq. $C u S O_{4}$ solution, the gas evolved at anode is:

S O_{2}

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S O_{3}

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O_{2}

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H_{2}

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Solution

The correct option is D $O_{2}$
$H_{2} O ⇌ H^{+} + O H^{-}$ . $H^{+}$ ions get discharged at cathode liberating $H_{2}$ gas. $O H^{-}$ ions get discharged at anode liberating $O_{2}$ gas.
At anode, $O H^{-}$ ions are discharged and oxidation takes place.
$4 O H^{-} \to 2 H_{2} O + O_{2}$

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In the electrolysis of aq. CuSO4 solution, the gas evolved at anode is:

The correct option is D O2H2O⇌H++OH− . H+ ions get discharged at cathode liberating H2 gas. OH− ions get discharged at anode liberating O2 gas.At anode, OH− ions are discharged and oxidation takes place.4OH−→2H2O+O2

In the electrolysis of aq. $C u S O_{4}$ solution, the gas evolved at anode is:

The correct option is D $O_{2}$
$H_{2} O ⇌ H^{+} + O H^{-}$ . $H^{+}$ ions get discharged at cathode liberating $H_{2}$ gas. $O H^{-}$ ions get discharged at anode liberating $O_{2}$ gas.
At anode, $O H^{-}$ ions are discharged and oxidation takes place.
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