In the electrolysis of,aqueous solution of copper sulphate using copper strips as the anode reaction is

{C u}^{2 +} + 2 e^{-} \to C u

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C u \to {C u}^{2 +} + 2 e^{-}

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2 {H O}^{-} \to H_{2} + 1 / 2 O_{2} + 2 e^{-}

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{S O}_{4}^{2 -} \to {S O}_{4} + 2 e^{-}

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Solution

The correct option is B $C u \to {C u}^{2 +} + 2 e^{-}$
At anode no. oxygen is produced , rather the copper anode dissolves.
Anode reaction :- $C u (s) \to C u^{2 +} (e q) + 2 e^{-}$
Hence Option $B$ is correct .

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E^{\circ}

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