In the electrolysis of $C u C l_{2}$ solution, the mass of cathode increased by $6.4 g$ . What occurred at copper anode?

0.224

liter of

C l_{2}

was liberated

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1.12

liter of oxygen was liberated

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0.05 m o l e C u^{2 +}

passed into the solution

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0.1 m o l e C u^{2 +}

passed into the solution

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Solution

The correct option is C $0.1 m o l e C u^{2 +}$ passed into the solution
In the electrolysis process,
reduction takes place at cathode and oxidation takes place at anode
so, if we increase the mass on cathode then same number of moles get oxidised at anode and go into the solution,
so, moles of Cu passed into the solution = $\frac{6.4}{63.5} = 0.1 m o l e$

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In the electrolysis of $C u C l_{2}$ solution, the mass of cathode increased by $6.4 g$ . What occurred at copper anode?