Question

In the electrolysis of dilute ${\mathrm{H}}_2{\mathrm{SO}}_4$ what is liberated at the anode?

Answer 1

The gas formed at anode and cathode:

• The dilute solution of sulfuric acid is electrolyzed, and gases are produced at both the anode and the cathode.
• ${\mathrm{OH}}^{-}$ being negatively charged, moves towards the anode (positively charged electrode), that is Oxygen gas is released at the anode.
• The reaction at anode OH − ion

$4{\mathrm{OH}}^{-}\to 2{\mathrm{H}}_2\mathrm{O}+{\mathrm{O}}_2+4{\mathrm{e}}^{-}$

Therefore, In the Electrolysis of a dilute solution of sulfuric acid, Oxygen gas is evolved at the anode