Question

In the electrolysis of very dilute NaOH using platinum electrodes:-

• A. $H_2$ is evolved at cathode and $O_2$ at anode
• B. $N{a}_2{O}_2$ is produced
  
• C. $H_2{O}_2$ is produced
  
• D. $O_2$ is produced at cathode and $H_2$ at anode

Answer 1

The correct option is A $H_2$ is evolved at cathode and $O_2$ at anode

Reduction and oxidation of $H_{2}O$ occurs to give $H_2$ at cathode and $O_2$ at anode.