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Question

In the electrolytic refining of copper using CuSO4 as the electrolyte, the anode reaction is

A
4OH(aq)O2(g)+2H2O(l)+4e
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B
Cu2+(aq)+2eCu(s)
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C
2SO24(aq)S2O28(aq)+2e
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D
Cu(s)Cu2+(aq)+2e
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Solution

The correct option is A 4OH(aq)O2(g)+2H2O(l)+4e
Anode is positively charged and hence, anions migrate towards it. We also know that oxidation occurs at anode. Out of OH and SO24, the former is easier to oxidise.
Hence, the following reaction occurs at anode:
4OH(aq)O2(g)+2H2O(l)+4e

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