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Idea of Hybridisation

In the electr...

Question

In the electronic configurations of elements $A a n d B$ are $1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{1} a n d 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{4}$ respectively, then the formula of the compound formes by the combination of these elements will be

A B

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A B_{3}

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A B_{2}

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A_{2} B

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Solution

The correct option is D $A_{2} B$
Electronic configuration of $A$ is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$
Electronic configuration of $B$ is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4}$
Valency of $A = 1$
Valency of $B = 8 - 6 = 2$
$∴$ The compound formed by $A & B$ is

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Similar questions

L, P, Q

R

L (l s^{2}, 2 S^{2}, 2 p^{4}); P (l s^{2}, 2 s^{2}, 2 P^{6}, 3 s^{1})

Q (l s^{2}, 2 s^{2} 2 P^{6}, 3 s^{2} 3 p^{5})

R (l s^{2}, 2 s^{2} 2 P^{6}, 3 s^{2})

X = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2}

Y = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}

X

Y

X = 2, 8, 2

Y = 2, 8, 7

L : 1 s^{2} 2 s^{2} 2 p^{4}

Q : 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}

P : 1 s^{2} 2 s^{2} 2 p^{6}, 3 s^{1}

R : 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}

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