In the Elligham diagram, graph for the formation of $C O_{2}$ from $C O$

Is a straight line with negative slope

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Is a straight line with positive slope

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Is a straight line almost parallel to temprature axis

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Is a curved line with sudden change in the slope

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Solution

The correct option is B Is a straight line with positive slope
During the reaction the gas is utilized so, the entropy becomes negative which leads to the positive value of the term, TΔS. So, slope ΔS comes positive for most of the reduction reaction.

For $C O + \frac{1}{2} O_{2} \to C O_{2}$ , the oxygen gas is consuming and the formed product is also a gas but the total number of gaseous species is decreasing so, the entropy decreasing so, for the oxidation reaction of carbon monoxide to carbon dioxide the slope is upward (positive slope).
Entropy remains constant during $C O_{2}$ formation.

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Similar questions

Q. The heat of carbon combustion with the

{C O}_{2}

formation, is

- 393.5 K J / m o l

, and the heat of

C O

combustion with the formation of

{C O}_{2}

, is

- 283 K J / m o l

. calculate the heat of combustion of carbon there in

C O

C + O_{2} \to C O_{2}; Δ H = - 94 K c a l;

C O + \frac{1}{2} O_{2} \to C O_{2}; Δ H = - 67.7 K c a l

On the basis of the above data, the heat of formation of

C O

is:

Q. What is the

△ H

of the reaction to form

C O_{2}

from

C O + O_{2}

in the given energy profile diagram?

Q. Mark the correct statement(s) based on the phase diagram of

C O_{2}

shown in the graph.

The heat of formation of CO $_{(g)}$ and CO $_{2 (g)}$ are $Δ$ H =- 110 and $Δ$ H = -393 kJ.mol $^{- 1}$ respectively. What is the heat of reaction ( $Δ$ H ) (in kJ.mol $^{- 1}$ ) for the following reaction $C O + \frac{1}{2} O_{2} \to C O_{2}$ ?

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In the Elligham diagram, graph for the formation of CO2 from CO

In the Elligham diagram, graph for the formation of $C O_{2}$ from $C O$