Question

In the equation, $Cu+xHN{O}_3\to Cu(N{O}_3{)}_2+yN{O}_2+2H_{2}O$, the values of $x$ and $y$ are :

• A. 3 and 5
• B. 8 and 6
• C. 4 and 2
• D. 7 and 1

Answer 1

The correct option is C 4 and 2

Applying POAC ( principle of atomic conservation) or the law of conservation of mass on $H$ and $N$ atoms.

Here are $4H$ on RHS of the equation.

Hence, the value of x should be $4$.

$N$ atoms on LHS of equation $=4$

$N$ atoms on RHS of equation is $=2+y$

$4=2+y$

$y=2$

So, overall reaction is, $Cu+4HN{O}_3\to Cu(N{O}_3{)}_2+2N{O}_2+2H_{2}O$.