In the equation x-p-q-x-q-p-q-x-p-p-x-q- x is not equal to

The correct option is D p+q x p/q+x q/p=q/x p+p/x q or xp p^2+qx q^2/pq=xq q^2+px p^2/(x p)(x a) or (x p) (x q) pq or x^2 + (p + q) ...

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Definition of Vector

In the equati...

Question

In the equation $\frac{x - p}{q} + \frac{x - q}{p} = \frac{q}{x - p} + \frac{p}{x - q}$ , $x$ is not equal to

0

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p + q

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p q

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\frac{p^{2} + q^{2}}{p + q}

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Solution

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p q x^{2} - (p^{2} + q^{2}) x + p q = 0,

x

2 [(x - p) (x - q) + (p - x) (p - q) + (q - x) (q - p)] = (p - q)^{2} + (x - p)^{2} + (x - q)^{2}

\frac{p + q}{p - q}, x

p^{2} - q^{2}

x

P = \frac{x}{x + y}, Q = \frac{y}{x + y}

\frac{1}{P - Q} - \frac{2 Q}{P^{2} - Q^{2}}

If the equation $x^{2} + p x + q = 0$ and $x^{2} + q x + p = 0$ have exactly one root in common, then equation with other roots is

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