In the equation of motion, $S = u t + 1 / 2 a t^{2}$ , S stands for

displacement in

t

seconds

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maximum height reached

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displacement in the

t^{t h}

second

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None of these

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Solution

The correct option is A displacement in $t$ seconds
$S = u t + \frac{1}{2} a t^{2}$
where
S= Distance traveled in the t seconds
u= Initial velocity of the motion
a= acceleration or retardation of the motion

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2 n d

(s = u t + \frac{1}{2} a t^{2})

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s = u t + \frac{1}{2} a t^{2}

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