Question

In the equation representing wave function,
$y=A\sin (kx-\omega t+{\varphi }_0)$
The term phase is defined as:

• A. ${\varphi }_0$
• B. ${\varphi }_0-\omega t$
• C. $kx+{\varphi }_0$
• D. $kx-\omega t+{\varphi }_0$

Answer 1

The correct option is D $kx-\omega t+{\varphi }_0$

Given,
$y=A\sin (kx-\omega t+{\varphi }_0)$
Phase of the wave is defined as the angle for $\sin$ function in the given wave function.
$\Rightarrow (kx-\omega t+{\varphi }_0)$ is the phase
Hence option $\left(d\right)$ is the correct answer.