In the equation y- A sin - kt- x - the dimensional formula for k is

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Standard XII

Physics

Dimensional Analysis

In the equati...

Question

In the equation $y = A s i n$ $[k t - \frac{x}{λ}],$ the dimensional formula for $k$ is

M^{0} L^{0} T^{- 1}

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M^{0} L^{0} T^{0}

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M^{0} {L T}^{0}

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{M L}^{0} T^{0}

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Solution

The correct option is A $M^{0} L^{0} T^{- 1}$
Each term in the bracket should be dimensionless.
$K t = M^{0} L^{0} T^{0}$
$K = M^{0} L^{0} T^{- 1}$

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Similar questions

Q. Match List I with II and select the correct answer:

List-I	List-II
A.Spring constant	1. $M^{1} L^{2} T^{- 2}$
B.pascal	2. $M^{0} L^{0} T^{- 1}$
C.hertz	3. $M^{1} L^{0} T^{- 2}$
D.joule	4. $M^{1} L^{- 1} T^{- 2}$

Q. Write the SI unit of the physical quantity having following dimensional formula

[M^{0} L^{2} T^{- 2} K^{- 1}]

Q. Match List I with List II and select the correct answer.

List - I	List - II
A) Spring constant	I) [ $M^{1} L^{2} T^{- 2}$ ]
B) Pascal	II) [ $M^{0} L^{0} T^{- 1}$ ]
C) Hertz	III)[ $M^{1} L^{0} T^{- 2}$ ]
D) Joule	IV) [ $M^{1} L^{- 1} T^{- 2}$ ]

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In the equation y=Asin [kt−xλ], the dimensional formula for k is

The correct option is A M0L0T−1Each term in the bracket should be dimensionless.Kt=M0L0T0K=M0L0T−1

In the equation $y = A s i n$ $[k t - \frac{x}{λ}],$ the dimensional formula for $k$ is

The correct option is A $M^{0} L^{0} T^{- 1}$
Each term in the bracket should be dimensionless.
$K t = M^{0} L^{0} T^{0}$
$K = M^{0} L^{0} T^{- 1}$