wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the equilibrium,2SO2+O22SO3 the partial pressure of SO2,O2 and SO3 are 0.662,0.10 and 0.331 respectively.What should be the partial pressure of oxygen so that the equilibrium concentration of SO2 and SO3 are equal?

A
0.4atm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1atm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.8atm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.25atm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 0.4atm

The given reaction,

2SO2+O22SO3

Partial pressure,

2SO2=0.662, O2=0.10, 2SO3=0.331

Kp=pSO32pSO22pO2


=[0.331]2[0.662]2[0.10]

=2.5

Now given that equilibrium condition,

pSO3=pSO2

Kp=pSO32pSO22pO2


2.5=1pO2

po2=12.5=0.4

Hence,

The partial pressure of Oxygen=0.4 atm

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Laws of Mass Action
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon