CameraIcon

SearchIcon

MyQuestionIcon

84

You visited us 84 times! Enjoying our articles? Unlock Full Access!

Law of Mass Action

In the equili...

Question

In the equilibrium, $2 {S O}_{2} + O_{2} ⇌ 2 S O_{3}$ the partial pressure of ${S O}_{2}, O_{2}$ and $S O_{3}$ are 0.662,0.10 and 0.331 respectively.What should be the partial pressure of oxygen so that the equilibrium concentration of ${S O}_{2}$ and $S O_{3}$ are equal?

A

0.4atm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

1atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

0.8atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

0.25atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 0.4atm
The given reaction,

$2 S O_{2} + O_{2} ⇋ 2 S O_{3}$

Partial pressure,

$2 S O_{2} = 0.662, O_{2} = 0.10, 2 S O_{3} = 0.331$

$K_{p} = \frac{{p_{S O_{3}}}^{2}}{{p_{S O_{2}}}^{2} p_{O_{2}}}$

$= \frac{{[0.331]}^{2}}{{[0.662]}^{2} [0.10]}$

$= 2.5$

Now given that equilibrium condition,
$p_{S O_{3}} = p_{S O_{2}}$
$K_{p} = \frac{{p_{S O_{3}}}^{2}}{{p_{S O_{2}}}^{2} p_{O_{2}}}$

$2.5 = \frac{1}{p_{O_{2}}}$

$p_{o_{2}} = \frac{1}{2.5} = 0.4$

Hence,
The partial pressure of $O x y g e n = 0.4 a t m$

Suggest Corrections

thumbs-up

0

Similar questions

Q. In the equilibrium

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)

, the partial pressure of

S O_{2}, O_{2}

S O_{3}

0.662, 0.10

0.331

atm respectively. What should be the partial pressure of oxygen so that the equilibrium concentrations of

S O_{2}

S O_{3}

Q. In the equilibrium

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)

, the partial pressures of

S O_{2}, O_{2}

S O_{3}

0.662, 0.101

0.331 a t m

respectively. What would be the partial pressure of oxygen so that the equilibrium concentration of

S O_{2}

S O_{3}

Q. At T(K), the partial pressures of

S O_{2}, O_{2}

S O_{3}

are 0.662, 0.100 and 0.331 atm, respectively for the reaction

{2 S O_{2}}_{(g)} + {O_{2}}_{(g)} ⇌ {2 S O_{3}}_{(g)}

at equilibrium. What is the partial pressure in atm, of

O_{2}

when the equilibrium partial pressures of

S O_{2}

S O_{3}

are equal at the same temperature ?

Q. The equilibrium constant

k_{p}

for the reaction

2 S O_{2} + O_{2} \Leftrightarrow 2 S O_{3}

a t m^{- 1}

. What would be the partial pressure of

O_{2}

, if the equilibrium pressures of

S O_{2}

S O_{3}

Q. In the equilibrium,

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g),

the equilibrium partial pressure of

S O_{2}, O_{2}

S O_{3}

0.6, 0.1

0.3

atm respectively. what would be the

K_{p}

?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Laws of Mass Action

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Law of Mass Action

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon