Question

In the equilibrium
$N{H}_{4}HS\left(s\right)\iff N{H}_3\left(g\right)+H_{2}S\left(g\right)$
the forward reaction can be favoured by:

• A. adding some more $N{H}_{4}HS$
• B. adding some more $N{H}_3$
• C. removing some $N{H}_3$ from the reaction mixture
• D. adding some more $H_{2}S$

Answer 1

The correct option is C removing some $N{H}_3$ from the reaction mixture

The equilibrium reaction is $N{H}_{4}HS\left(s\right)\iff N{H}_3\left(g\right)+H_{2}S\left(g\right)$.
When some ammonia is removed from the equilibrium mixture, the equilibrium will shift to right so that more ammonia is formed which will nullify the effect of removal of ammonia.
Thus the removal of ammonia will favor the forward reaction.