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Characteristics of Equilibrium Constant

In the equili...

Question

In the equilibrium : $S O_{2} C l_{2} (g) ⇌ S O_{2} (g) + C l_{2} (g)$ at $2000$ K and $10$ atm pressure, % $C l_{2} =$ % $S O_{2} = 40$ (by volume). Then $K_{p}$ is

A

K_{c} = 0.1 m o l L^{- 1}

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B

\frac{n (S O_{2} C l_{2})}{n (S O_{2})} = \frac{1}{4}

at equilibrium

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C

n (S O_{2} C l_{2}) = n (S O_{2}) = n (C l_{2})

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D

K_{p} = 8

atm

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Solution

The correct option is D $K_{p} = 8$ atm
Since, volume is proportional to number of moles and number of moles is proportional to pressure at fixed volume. So,

$S O_{2} C l_{2}$ $⟶$ $S O_{2}$ $+$ $C l_{2}$

100 0 0

20 40 40

2 atm 4 atm 4 atm

$K_{p} = \frac{P_{S O_{2}} \times P_{C l_{2}}}{P_{S O_{2} C l_{2}}} = \frac{4 \times 4}{2} = 8 a t m$

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Similar questions

{S O}_{2}

{C l}_{2}

are introduced into a

3 L

vessel. Partial pressure of

{S O}_{2} {C l}_{2}

{C l}_{2}

at equilibrium are

1

2

atm respectively. The value of

K_{p}

for the following reaction is

10

{S O}_{2} {C l}_{2} (g) ⇌ {S O}_{2} (g) + {C l}_{2} (g)

What will be the total pressure in atm at equilibrium?

Q. The equilibrium constant

K_{p}

for the reaction,

S O_{2} C l_{2} (g) ⇌ S O_{2} (g) + C l_{2} (g)

is 1.125 atm at temperature T. Select the correct statements for dissociation of pure

S O_{2} C l_{2}

(g) at equilibrium state of 2 atm equilibrium pressure and temperature T:

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)

P C l_{5}

be put in a container of volume V litre and at equilibrium, x moles of it was decomposed, find its

K_{p}

K_{c}

at equilibrium pressure of P atm.

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)

P C l_{5}

be put in a container of volume V litre and at equilibrium, x moles of it was decomposed, find its

K_{p}

K_{c}

at equilibrium pressure of P atm.

10 l i t r e

O_{3}

O_{2}

at equilibrium at 2000 K.

K_{p} = 4 \times 10^{14}

2 O_{3} (g) ⇌ 3 O_{2} (g)

P_{O_{2}} >> P_{O_{3}}

and if total pressure is 8 atm, then patial pressure of

O_{3}

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