Question

In the esterification of an organic acid R-COOH by alcohol R'OH, O of acid is isotopic.
$R-\stackrel{\stackrel{O}{\parallel }}{C}-\stackrel{18}{O}H+R^{\prime }-O-H\to R-\stackrel{\stackrel{O}{\parallel }}{C}-O{R}^{\prime }+H_{2}O$

Which of the following statement is correct?

• A. ${}^{18}O$ is in ester
• B. ${}^{18}O$ is in water
• C. ${}^{18}O$ is in both
• D. ${}^{18}O$ is in none

Answer 1

The correct option is B ${}^{18}O$ is in water

According to mechanism, ${}^{18}O$ goes with water